Mat
102
Quiz
4
1.
A school district obtained 50 new computers which are to be apportioned to its
4 schools according to the number of students. Use the Webster’s method.
Show your work!
standard divisor= 14 Modified divisor = 14.1
|
School |
Number
of students |
SQ |
[SQ]
|
D=15 MQ |
[MQ] |
D=14.1 |
Webster’s |
|
Clayton |
203 |
14.5 |
15 |
13.53 |
14 |
14 |
14 |
|
O’Reilly |
124 |
8.86 |
9 |
8.27 |
8 |
9 |
9 |
|
King
|
83 |
5.93 |
6 |
5.53 |
6 |
6 |
6 |
|
Hughes |
290 |
20.71 |
21 |
19.33 |
19 |
21 |
21 |
|
total |
700 |
|
51 too high |
|
47 too low |
50 |
50 |
2.
Another district (with 2046 students) has received 25 computers which they
apportion using Huntington-Hill method. The following are the modified
quotas:
|
School |
Number
of students |
MQ |
HH
apportionment |
|
A |
457 |
4.4804 |
5 |
|
B |
1069 |
10.4804 |
10 |
|
C
|
520 |
5.0980 |
5 |
|
Total
|
2046 |
|
20 |
What was the modified divisor? 102
Explain how you rounded 4.4804 and why. Up, because
it is larger than geometric mean of 4 and 5, which is 
4.4721
Explain how you rounded 10.4804 and why Down, because
it is smaller than geom. mean of 10 and 11, which is 
4.48808.