Christian Aebi's "13" problem



2^k - 2 -
2 - 2^k -
- 2^k - 2
- 2 - 2^k
- 3^l - -
1B
2B
4A
3A
- - 3^l -
3B
4B
2A
1A
3 - - 3^l
7B, 9A
8A
6A
5A
3^l - - 3
5B
6B
8B
7A, 9B



Copyright 2003 George Baloglou